X^2+200x-16100=0

Solution for X^2+200x-16100=0 equation:

X^2+200X-16100=0

a = 1; b = 200; c = -16100;
Δ = b2-4ac
Δ = 2002-4·1·(-16100)
Δ = 104400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{104400}=\sqrt{3600*29}=\sqrt{3600}*\sqrt{29}=60\sqrt{29}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-60\sqrt{29}}{2*1}=\frac{-200-60\sqrt{29}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+60\sqrt{29}}{2*1}=\frac{-200+60\sqrt{29}}{2}
$